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Wireway Fill Calculator — 20% Fill & >30 Conductor Check

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Calculated result

15.63% fill — PASS

Interior area: 16 in²

Conductor area: 2.5 in² of 3.2 in² allowed

Minimum interior area at 20%: 12.5 in² (equivalent square 3.536 in × 3.536 in)

18 current-carrying conductors — no >30 wireway adjustment trigger from this count

Splice/tap area not entered; 75% point-fill check not evaluated.

Show the working
  1. 1. Interior area = 4 in × 4 in = 16 in².
  2. 2. 20% conductor allowance = 16 in² × 0.20 = 3.2 in².
  3. 3. Actual fill = 2.5 in² ÷ 16 in² × 100 = 15.63%.
  4. 4. Required interior area = 2.5 in² ÷ 0.20 = 12.5 in².
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