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Wireway Fill Calculator — 20% Fill & >30 Conductor Check
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Calculated result
15.63% fill — PASS
Interior area: 16 in²
Conductor area: 2.5 in² of 3.2 in² allowed
Minimum interior area at 20%: 12.5 in² (equivalent square 3.536 in × 3.536 in)
18 current-carrying conductors — no >30 wireway adjustment trigger from this count
Splice/tap area not entered; 75% point-fill check not evaluated.
Show the working
- 1. Interior area = 4 in × 4 in = 16 in².
- 2. 20% conductor allowance = 16 in² × 0.20 = 3.2 in².
- 3. Actual fill = 2.5 in² ÷ 16 in² × 100 = 15.63%.
- 4. Required interior area = 2.5 in² ÷ 0.20 = 12.5 in².
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