MAXScanner electronics calculator
Updated 2026-09-16
Inductor Energy Calculator — Joules, Current & Magnetic Storage
Calculate ideal magnetic energy stored in an inductor from current and inductance entered in mH, with results in joules, millijoules and microjoules.
Inputs
Results
Energy 0.02 J
20 mJ
20,000 µJ
More actions
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Your calculation, step by step
- 1.L = 10 mH = 0.01 H.
- 2.Energy: E = ½LI² = 0.5 × 0.01 × 2² = 0.02 J.
Formula, example and limits
E=½LI²; L in henries (mH÷1000), I in amps, E in joules.
10 mH carrying 2 A stores 0.02 J.
- Inductance is treated as constant at the entered current.
- Core saturation and winding losses are excluded.
Frequently asked questions
Why is current squared?
Ideal stored magnetic energy grows with I², so doubling current quadruples energy.
Does this include copper loss?
No. I²R heating is dissipative loss, not stored magnetic energy.