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Electrical & Engineering Calculators

RC Time Constant Calculator — Solve τ, R or C + Cutoff & Timing

Calculate RC time constant from resistance and capacitance or solve backward for resistance or capacitance from a target tau, with five-tau settling, first-order cutoff and charge/discharge timing.

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Calculated result

τ = 1,000 ms

Solved RC set: 10 kΩ · 100 µF · τ 1,000 ms

5τ settling reference: 5 s · ideal charge ≈ 99.326%

First-order cutoff: 0.159155 Hz

Time to 90% charge: 2.302585 s

Time to 10% remaining on discharge: 2.302585 s

Charge reference: 1τ 63.212% · 3τ 95.021% · 5τ 99.326%

Show the working
  1. 1. τ = 10 kΩ × 100 µF = 1,000 ms.
  2. 2. fc = 1 ÷ (2π × 1 s) = 0.159154943 Hz.
  3. 3. Charge target time = −τ ln(1 − 0.9) = 2.302585093 s.
  4. 4. Discharge target time = −τ ln(0.1) = 2.302585093 s.

Ideal first-order RC model. Component tolerance, leakage, ESR, source impedance and connected load can shift real timing.

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The calculation, without hidden assumptions

An ideal first-order RC circuit is governed by τ = R×C. Strong RC work often starts in either direction: calculate tau from known component values, or start from a target timing constant and solve the missing resistor or capacitor. MAXScanner supports all three modes, then uses the solved RC product to show five-tau settling, the −3 dB cutoff 1/(2πRC), and exact charge/discharge target times without pretending real parts are tolerance-free.

How to use this calculator

1

Choose whether to solve the time constant, resistance or capacitance.

2

Enter the two known quantities using practical units; reverse-solve modes use the target time constant plus the known component.

3

Review the solved value, 5τ, cutoff frequency and exact charge/discharge target times, then account for component tolerances in real hardware.

Where people use it

  • RC delay and debounce timing
  • Choosing a resistor or capacitor for a target tau
  • First-order low-pass/high-pass corner checks
  • Capacitor charge and discharge timing

Example: 10 kΩ and 100 µF

R×C = 10,000×0.0001 = 1 second. The same relationship can be solved backward: with 100 µF and a 1 s target tau, R = 10 kΩ.

What the result does not assume

  • Real capacitors and resistors have tolerance, leakage, ESR, source resistance and load effects that can shift measured timing.
  • The cutoff result is the ideal first-order RC pole magnitude; an actual surrounding circuit can change the transfer function.

Frequently asked questions

Can I solve for resistance or capacitance from a target time constant?+

Yes. Choose resistance or capacitance as the target, enter tau plus the other component value, and the calculator rearranges τ = RC.

What happens after one RC time constant?+

An ideal charging capacitor reaches about 63.2% of its final step voltage; during discharge about 36.8% remains.

Is a capacitor fully charged after 5τ?+

Not mathematically. At 5τ an ideal charging capacitor is about 99.33% of its final value, which is often treated as practically settled.

How is RC cutoff frequency related to tau?+

fc = 1/(2πτ), so a larger time constant produces a lower first-order corner frequency.

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